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标题: ios - 在 UIAlertView 试图查看两个文本字段。它显示文本字段数组iOS7的错误范围 [打印本页]

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作者: 菜鸟教程小白    时间: 2022-12-12 09:30
标题: ios - 在 UIAlertView 试图查看两个文本字段。它显示文本字段数组iOS7的错误范围

您好，我正在尝试查看 UIAlertView 中的两个文本字段，但显示错误。我已经使用下面的代码来查看文本字段。

- (void)viewDidLoad
{
    [super viewDidLoad];

    UIAlertView * alert = [[UIAlertView alloc] initWithTitle"Hello!"
                                                     message"lease enter your details:"
                                                    delegate:self
                                           cancelButtonTitle"Continue"
                                           otherButtonTitles:nil];
    alert.alertViewStyle = UIAlertViewStylePlainTextInput;

    UITextField * name = [alert textFieldAtIndex:0];
    name.keyboardType = UIKeyboardTypeAlphabet;
    name.placeholder = @"Enter your name";

    UITextField * phone = [alert textFieldAtIndex:1];
    phone.keyboardType = UIKeyboardTypeNumberPad;
    phone.placeholder = @"Enter your phone";

    [alert show];
    [alert release];
}

我已经使用上面的代码查看了两个文本文件，但我越来越喜欢了。 'textFieldIndex (1) 超出了文本字段数组的范围'

请告诉我我在上面的代码中哪里做错了，请告诉我解决这个问题。

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Best Answer-推荐答案

查看 UIAlertView.h 文件

/* Retrieve a text field at an index - raises NSRangeException when textFieldIndex is out-of-bounds. The field at index 0 will be the first text field (the single field or the login field), the field at index 1 will be the password field. */

- (UITextField *)textFieldAtIndexNSInteger)textFieldIndex NS_AVAILABLE_IOS(5_0);

这样做:

alert.alertViewStyle = UIAlertViewStyleLoginAndPasswordInput;

UITextField * name = [alert textFieldAtIndex:0];
name.keyboardType = UIKeyboardTypeAlphabet;
name.placeholder = @"Enter your name";

UITextField * phone = [alert textFieldAtIndex:1];
phone.secureTextEntry = NO;
phone.keyboardType = UIKeyboardTypeNumberPad;
phone.placeholder = @"Enter your phone";

关于ios - 在 UIAlertView 试图查看两个文本字段。它显示文本字段数组iOS7的错误范围，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/23193317/

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