ios - tableview segue 到另一个 View Controller

我是编程新手，可能被一个简单的问题挂断了。我在我的表格 View 中为我的数组使用解析。选择该行后，我想转到另一个 View Controller 上的搜索栏。 segue 工作正常，tableview 工作正常，但我似乎无法让 objectId 通过。

#import "bookmarkViewController.h"
#import "arse/Parse.h"
#import <arseUI/ParseUI.h>
#import "ViewController.h"

@implementation bookmarkViewController

@synthesize postArray;


#pragma mark - View lifecycle

- (void)viewDidLoad
{
    [super viewDidLoad];

    [self.navigationItem setLeftBarButtonItem:[[UIBarButtonItem alloc]                
initWithBarButtonSystemItem:UIBarButtonSystemItemRefresh target:self      
actionselector(refreshButtonHandler]];

}

- (void)viewWillAppearBOOL)animated
{
    if ([PFUser currentUser])
        [self refreshButtonHandler:nil];
}

#pragma mark - Button handlers

- (void)refreshButtonHandlerid)sender
{
    //Create query for all Post object by the current user
    PFQuery *postQuery = [PFQuery queryWithClassName"ost"];
    [postQuery whereKey"author" equalTo:[PFUser currentUser]];

    // Run the query
    [postQuery findObjectsInBackgroundWithBlock:^(NSArray *objects, NSError *error) {
        if (!error) {
            //Save results and update the table
            postArray = objects;
            [self.tableView reloadData];
        }
    }];
}

#pragma mark - Table view data source

- (NSInteger)tableViewUITableView *)tableView numberOfRowsInSection:     
(NSInteger)section
{
    // Return the number of rows in the section.
    return postArray.count;
}

- (UITableViewCell *)tableViewUITableView *)tableView cellForRowAtIndexPath:   
(NSIndexPath *)indexPath
{
    static NSString *CellIdentifier = @"Cell";

    UITableViewCell *cell = [tableView   
dequeueReusableCellWithIdentifier:CellIdentifier];
    if (cell == nil) {
        cell = [[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault  
reuseIdentifier:CellIdentifier];
    }

    // Configure the cell with the textContent of the Post as the cell's text label
    PFObject *post = [postArray objectAtIndex:indexPath.row];
    [cell.textLabel setText:[post objectForKey"textContent"]];

    return cell;
}

- (void)tableViewUITableView *)tableView didSelectRowAtIndexPathNSIndexPath    
*)indexPath{
    NSLog(@"cell tapped");
    PFObject *post = [postArray objectAtIndex:indexPath.row];
    NSLog(@"%@", post.objectId);
    [self performSegueWithIdentifier"searchBookmark" sender:self];



}
- (void)prepareForSegueUIStoryboardSegue *)segue senderid)sender
{
    ViewController *vc = [segue destinationViewController];

    vc.labelText = post.objectId;    
  }
}


@end

在 vc.label.text 中，我总是使用未声明的标识符“post”，但我似乎不知道如何识别它。就是在上面的方法中。

NSLogs 正确回复 16:17:27.513 [App] 单元被点击 [应用] cgdVY7Eu9h

---

Best Answer-推荐答案

将您的 didSelectRowAtIndexPath 和 prepareForSegue 更改为:

- (void)tableViewUITableView *)tableView didSelectRowAtIndexPathNSIndexPath* )indexPath{
    [self performSegueWithIdentifier"searchBookmark" sender:self];
}

- (void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender

{
    NSIndexPath *indexPath = [self.tableView indexPathForSelectedRow];

    NSLog(@"cell tapped");
    PFObject *post = [postArray objectAtIndex:indexPath.row];
    NSLog(@"%@", post.objectId);
    ViewController *vc = [segue destinationViewController];

    vc.labelText = post.objectId;    
    }
}

关于ios - tableview segue 到另一个 View Controller ，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/27238999/