integer - C# does not convert Number with int.TryParse

Question

Closed. This question is not reproducible or was caused by typos. It is not currently accepting answers. question from:https://stackoverflow.com/questions/65909015/c-sharp-does-not-convert-number-with-int-tryparse

Answer 1

There is a decimal separator in your value. This suggests it is not an integer but actually a decimal (or real) value.

You should use decimal.TryParse() or double.TryParse() rather than int.TryParse() then cast the result to int.

string val = "17.0";

decimal d = 0;
int i = 0;

if (!decimal.TryParse(val, NumberStyles.AllowDecimalPoint, CultureInfo.InvariantCulture, out d))
{
    Console.WriteLine("Not a decimal");
}
else
{
    i = (int)d;
    Console.WriteLine(i);
}