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How to replicate vector in c?

In the days before c++ and vector/lists, how did they expand the size of arrays when they needed to store more data?

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Vector and list aren't conceptually tied to C++. Similar structures can be implemented in C, just the syntax (and error handling) would look different. For example LodePNG implements a dynamic array with functionality very similar to that of std::vector. A sample usage looks like:

uivector v = {};
uivector_push_back(&v, 1);
uivector_push_back(&v, 42);
for(size_t i = 0; i < v.size; ++i)
    printf("%d
", v.data[i]);
uivector_cleanup(&v);

As can be seen the usage is somewhat verbose and the code needs to be duplicated to support different types.

nothings/stb gives a simpler implementation that works with any types:

double *v = 0;
arrpush(v, 1.0);
arrpush(v, 42.0);
for(int i = 0; i < arrlen(v); ++i)
    printf("%g
", v[i]);
arrfree(v);

It also provides hash maps, and the trick it uses for type-safe containers in C can be applied to other generic containers too.

Any of these methods can expand the underlying storage either by a call to realloc (see below), or by allocating new storage with malloc and freeing the old one with free -- which is equivalent to how std::vector grows its memory in C++.


A lot of C code, however, resorts to managing the memory directly with realloc:

void* newMem = realloc(oldMem, newSize);
if(!newMem) {
    // handle error
}
oldMem = newMem;

Note that realloc returns null in case of failure, yet the old memory is still valid. In such a situation this common (and incorrect) usage leaks memory:

oldMem = realloc(oldMem, newSize);
if(!oldMem) {
    // handle error
}

Compared to std::vector and the C equivalents from above, the simple realloc method does not provide O(1) amortized guarantee, even though realloc may sometimes be more efficient if it happens to avoid moving the memory around.


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