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in Technique[技术] by (71.8m points)

Search for a value in a nested dictionary python

Search for a value and get the parent dictionary names (keys):

Dictionary = {dict1:{
        'part1': {
            '.wbxml': 'application/vnd.wap.wbxml',
            '.rl': 'application/resource-lists+xml',    
        },
        'part2':
            {'.wsdl': 'application/wsdl+xml',
            '.rs': 'application/rls-services+xml',
            '.xop': 'application/xop+xml',
            '.svg': 'image/svg+xml',
            },
        'part3':{...}, ...

   dict2:{
          'part1': {    '.dotx': 'application/vnd.openxmlformats-..'                           
            '.zaz': 'application/vnd.zzazz.deck+xml',
            '.xer': 'application/patch-ops-error+xml',}  
          },
          'part2':{...},
          'part3':{...},...  

    },...

In above dictionary I need to search values like: "image/svg+xml". Where, none of the values are repeated in the dictionary. How to search the "image/svg+xml"? so that it should return the parent keys in a dictionary { dict1:"part2" }.

Please note: Solutions should work unmodified for both Python 2.7 and Python 3.3.

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Here's a simple recursive version:

def getpath(nested_dict, value, prepath=()):
    for k, v in nested_dict.items():
        path = prepath + (k,)
        if v == value: # found value
            return path
        elif hasattr(v, 'items'): # v is a dict
            p = getpath(v, value, path) # recursive call
            if p is not None:
                return p

Example:

print(getpath(dictionary, 'image/svg+xml'))
# -> ('dict1', 'part2', '.svg')

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