Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
380 views
in Technique[技术] by (71.8m points)

javascript - How can I make this call to request in nodejs synchronous?

I have a function in my nodejs application called get_source_at. It takes a uri as an argument and its purpose is to return the source code from that uri. My problem is that I don't know how to make the function synchronously call request, rather than giving it that callback function. I want control flow to halt for the few seconds it takes to load the uri. How can I achieve this?

function get_source_at(uri){
    var source;
    request({ uri:uri}, function (error, response, body) {
        console.log(body);
    });
    return source;
}

Also, I've read about 'events' and how node is 'evented' and I should respect that in writing my code. I'm happy to do that, but I have to have a way to make sure I have the source code from a uri before continuing the control flow of my application - so if that's not by making the function synchronous, how can it be done?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

You can with deasync:

function get_source_at(uri){
    var source;
    request({ uri:uri}, function (error, response, body) {
        source = body;
        console.log(body);
    });
    while(source === undefined) {
      require('deasync').runLoopOnce();
    }
    return source;
}

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...