Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
551 views
in Technique[技术] by (71.8m points)

scala - Operate on neighbor elements in RDD in Spark

As I have a collection:

List(1, 3,-1, 0, 2, -4, 6)

It's easy to make it sorted as:

List(-4, -1, 0, 1, 2, 3, 6)

Then I can construct a new collection by compute 6 - 3, 3 - 2, 2 - 1, 1 - 0, and so on like this:

for(i <- 0 to list.length -2) yield {
    list(i + 1) - list(i)
}

and get a vector:

Vector(3, 1, 1, 1, 1, 3)

That is, I want to make the next element minus the current element.

But how to implement this in RDD on Spark?

I know for the collection:

List(-4, -1, 0, 1, 2, 3, 6)

There will be some partitions of the collection, each partition is ordered, can I do the similar operation on each partition and collect results on each partition together?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

The most efficient solution is to use sliding method:

import org.apache.spark.mllib.rdd.RDDFunctions._

val rdd = sc.parallelize(Seq(1, 3,-1, 0, 2, -4, 6))
  .sortBy(identity)
  .sliding(2)
  .map{case Array(x, y) => y - x}

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...