javascript - Nodejs: get filename of caller function

Question

I wonder how-to get an absolute path of a caller of a function?

Let say that:

in file a.js I call b(); b() is a function defined in file b.js. a.jsrequires b . So how do I get a.js absolute path from b.js in node?

Answer 1

Failing to restore the prepareStackTrace function can cause issues. Here's an example that removes side-effects

function _getCallerFile() {
    var originalFunc = Error.prepareStackTrace;

    var callerfile;
    try {
        var err = new Error();
        var currentfile;

        Error.prepareStackTrace = function (err, stack) { return stack; };

        currentfile = err.stack.shift().getFileName();

        while (err.stack.length) {
            callerfile = err.stack.shift().getFileName();

            if(currentfile !== callerfile) break;
        }
    } catch (e) {}

    Error.prepareStackTrace = originalFunc; 

    return callerfile;
}