It's quite simple actually, dequeue
will create a promise that enqueue
will resolve. We just have to keep the resolvers in a queue - and also care about the case where values are enqueued before they are dequeued, keeping the already fulfilled promises in a queue.
class AsyncBlockingQueue {
constructor() {
// invariant: at least one of the arrays is empty
this.resolvers = [];
this.promises = [];
}
_add() {
this.promises.push(new Promise(resolve => {
this.resolvers.push(resolve);
});
}
enqueue(t) {
// if (this.resolvers.length) this.resolvers.shift()(t);
// else this.promises.push(Promise.resolve(t));
if (!this.resolvers.length) this._add();
this.resolvers.shift()(t);
}
dequeue() {
if (!this.promises.length) this._add();
return this.promises.shift();
}
// now some utilities:
isEmpty() { // there are no values available
return !this.promises.length; // this.length <= 0
}
isBlocked() { // it's waiting for values
return !!this.resolvers.length; // this.length < 0
}
get length() {
return this.promises.length - this.resolvers.length;
}
[Symbol.asyncIterator]() {
return {
next: () => this.dequeue().then(value => ({done: false, value}))
};
}
}
I don't know TypeScript, but presumably it's simple to add the the necessary type annotations.
For better performance, use a Queue implementation with circular buffers instead of plain arrays, e.g. this one. You might also use only a single queue and remember whether you currently store promises or resolvers.
与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…