I'm surprised at how it is possible to continue execution even after a StackOverflowError
has occurred in Java.
I know that StackOverflowError
is a sublass of the class Error.
The class Error is decumented as "a subclass of Throwable that indicates serious problems that a reasonable application should not try to catch."
This sounds more like a recommendation than a rule, subtending that catching a Error like a StackOverflowError is in fact permitted and it's up to the programmer's reasonability not to do so. And see, I tested this code and it terminates normally.
public class Test
{
public static void main(String[] args)
{
try {
foo();
} catch (StackOverflowError e) {
bar();
}
System.out.println("normal termination");
}
private static void foo() {
System.out.println("foo");
foo();
}
private static void bar() {
System.out.println("bar");
}
}
How can this be? I think by the time the StackOverflowError is thrown, the stack should be so full that there is no room for calling another function. Is the error handling block running in a different stack, or what is going on here?
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