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javascript - Get the referrer, paid/natural and keywords for the current visitor with Google Analytics

Is it possible to get the following information about the current visitor using Google Analytics API with JavaScript?

  • Referrer site ('Source' in GA)
  • Paid or natural ('Medium' in GA)
  • Keyword
  • First time/returning
  • Number of visits

If it's not possible with Google Analytics API is there any other easy way to do it (apart from parsing HTTP Referer, storing the visits statistics in DB etc.)?

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If you're still using ga.js (the legacy version of Google Analytics tracking code), you can use the below code to generate the values you want within the browser, by reading browser cookies. (Most people will have migrated to analytics.js, which does not store the campaign information in the __utmz cookie.)

I assume you have a function called readCookie(); I tend to use the one from QuirksMode

For referral, medium, and campaign information:

var utmz = readCookie('__utmz'); //using a cookie reading function
var vals = (function() {
        var pairs = utmz.split('.').slice(4).join('.').split('|');
        var ga = {};
        for (var i = 0; i < pairs.length; i++) {
            var temp = pairs[i].split('=');
                ga[temp[0]] = temp[1];
        }
        return ga;
    })();

//vals.utmcmd: medium (organic, referral, direct, etc)
//vals.utmcsr: source (google, facebook.com, etc)
//vals.utmcct: content (index.html, etc)
//vals.utmccn: campaign 
//vals.utmctr: term (search term)
//vals.utmgclid: adwords-only (value is irrelevant, but means its AdWords autotagged traffic, but it implies that medium=cpc, even though it'll be set to `(none)` or `(not%20set)`

For pageview count and visit count:

var pageviews = readCookie('__utmz').split('.')[1];
var visits = readCookie('__utma').split('.').pop() //returns number of visits

Obviously, if (+visits)===1, then its a first time visitor. (Remember: values from cookies will be strings, so you'll need to cast them to numbers to safely do numeric comparisons, even though JS is loosely typed.


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