I cannot find out how to obtain destination element with jQuery UI sortable.
$("#pages").sortable({
opacity: 0.6,
update: function(event, ui) {
var first = ui.item; // First element to swap
var second = ???? // Second element to swap
swapOnServer(first, second);
}
});
All the options I've tried point to the element being dragged, but not the one it is swapped with: ui.item[0]
, event.srcElement
, event.toElement
.
Additionally, this
points to the LIST (OL) element.
Saying second I mean following:
Original order is:
| 0 | 1 | 2 | 3 |
We drag element 1 and drop it in position 3. Which will end up with:
| 0 | 3 | 2 | 1 |
So the first element is 1 and the second is 3 (WRONG! See below).
UPDATE: I have realised that I got it wrong. The new order in this case will be.
| 0 | 2 | 3 | 1 |
As a result my question does not really makes sense. Thanks everybody for the help. I'll mark vote and mark an answer.
So the question is how to obtain the second element here?
THE CURRENT WORKAROUND (as there is no term as swapping in sortable) is below. It uses temporary array with orders.
var prevPagesOrder = [];
$("#pages").sortable({
start: function(event, ui) {
prevPagesOrder = $(this).sortable('toArray');
},
update: function(event, ui) {
var currentOrder = $(this).sortable('toArray');
var first = ui.item[0].id;
var second = currentOrder[prevPagesOrder.indexOf(first)];
swapOnServer(first, second);
}
});
Thanks,
Dmitriy.
See Question&Answers more detail:
os 与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…