Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
130 views
in Technique[技术] by (71.8m points)

javascript - Replace current page with ajax content

I have a page with a dialog window which sends ajax post data to server and receives a response. During development, there can be two responses - one regular (this is not the question) or one with an error. Server returns code 500 and a page with lot of debug informations. This is a regular page returned from a framework and contains some javascript code. I want to be able to display this error page in case it happens.

The problem is, I can not simply attach the returned result to body element or open a new link in a new page and load this error again. I simply get a html page instead of data and I have to display the page (in current window or in another one).

I am using jQuery.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

Configure jQuery ajax setup as follows:

$.ajaxSetup({
    error: handleXhrError
});

where handleXhrError function look like this:

function handleXhrError(xhr) {
    document.open();
    document.write(xhr.responseText);
    document.close();
}

See also:


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...