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in Technique[技术] by (71.8m points)

javascript - Uncaught TypeError: $.ajax(...).success is not a function

I'm new to jQuery and using a little old tutorial on node.js that uses this snippet :

$(function () {    
    var roomId;

    $.ajax({
        type: "GET",
        url: "/api/rooms"
    }).success(function (rooms) { 
        roomId = rooms[0].id;
        getMessages();
        $.each(rooms, function (key, room) {
            var a = '<a href="#" data-room-id="' + room.id + '" class="room list-group-item">' + room.name + '</a>';
            $("#rooms").append(a);
        });

    });

    [...]       

});

However I get this error

Uncaught TypeError: $.ajax(...).success is not a function

at }).success(function (rooms) {

I'm wondering what can be wrong here?

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1 Reply

0 votes
by (71.8m points)

The call to ajax should look like:

$.ajax({
    type: "GET",
    url: "/api/rooms",
    success: function (rooms) { 

    }
});

You don't method chain the success function, it is one of the entries in the dictionary argument.


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