Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
237 views
in Technique[技术] by (71.8m points)

javascript - Autocomplete using a trie

I am working on an autocompletion script and was thinking about using a trie. My problem is I want everything that matches to be returned. So for example I type in the letter r I want all entries starting with r to be returned. Then all entries starting with re etc. Is this feasible with a trie and how would it work. Also, if there is a better way I am open to suggestions. The reason I ask is it seems like it would be complicated and a whole lot of processing to return all of the nodes off of say the r branch.

And yes I may be reinventing the wheel, but I would like to learn how it works.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

You can absolutely do it using a trie. Here is some code I threw together that can point you in the right direction:

var tokenTree = function (tokenArray) {
  var createLetterObject = function (l) {
    var pChildren = [];

    var getMatchingWords = function (characterArr, availableWords, children) {
        if (characterArr.length === 0) {
            for (var child in children) {
                if ({}.hasOwnProperty.call(children, child)) {
                    var currentChild = children[child];

                    var words = currentChild.getWords(characterArr);

                    for (var pos in words) {
                        if ({}.hasOwnProperty.call(words, pos)) {
                            availableWords.push(words[pos]);
                        }
                    }

                    if (currentChild.word) {
                        availableWords.push(currentChild.word);
                    }
                }
            }
        } else {
            var currentCharacter = characterArr.pop();
            getMatchingWords(characterArr, availableWords, children[currentCharacter].children);
        }
    };

    function doGetWords(wordPart) {
        var len = wordPart.length;
        var ar = [];
        var wordList = [];

        for (var ii = len - 1; ii >= 0; ii --) {
            ar.push(wordPart[ii].toUpperCase());
        }

        getMatchingWords(ar, wordList, pChildren);

        return wordList;
    }

    return {
        letter: l,
        children: pChildren,
        parent: null,
        word: null,
        getWords: doGetWords
    };
};

var startingPoint = createLetterObject();

function parseWord(wordCharacterArray, parent, fullWord) {
    if (wordCharacterArray.length === 0) {
        parent.word = fullWord;
        return;
    }

    var currentCharacter = wordCharacterArray.pop().toUpperCase();

    if (!parent.children[currentCharacter]) {
        parent.children[currentCharacter] = createLetterObject(currentCharacter);
    }

    parseWord(wordCharacterArray, parent.children[currentCharacter], fullWord);
}

for (var counter in tokenArray) {
    if ({}.hasOwnProperty.call(tokenArray, counter)) {
        var word = tokenArray[counter];

        if (!word) {
            continue;
        }

        var ar = [];

        var wordLength = word.length;

        for (var ii = wordLength - 1; ii >= 0; ii--) {
            ar.push(word[ii]);
        }

        parseWord(ar, startingPoint, word);
    }
}

  return startingPoint;
};

Usage

var tokens = ["Token", "words", "whohaa", "mommy", "test", "wicked"];
var tree = tokenTree(tokens);
var currentTokenSet = 'w'; 
var list = tree.getWords(currentTokenSet);

// it will return words,whohaa,wicked.
console.log(list) 

I'm not saying this is anywhere near the best or most efficient way, but it should at least get you pointed in the right direction.

Here is a jsfiddle showing it working: https://jsfiddle.net/es6xp8h9/


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...