Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
145 views
in Technique[技术] by (71.8m points)

java - How to read several resource files with the same name from different JARs?

If there are two JAR files in the classpath, both containing a resource named "config.properties" in its root. Is there a way to retrieve both files similar to getClass().getResourceAsStream()? The order is not relevant.

An alternative would be to load every property file in the class path that match certain criterias, if this is possible at all.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

You need ClassLoader.getResources(name)
(or the static version ClassLoader.getSystemResources(name)).

But unfortunately there's a known issue with resources that are not inside a "directory". E.g. foo/bar.txt is fine, but bar.txt can be a problem. This is described well in the Spring Reference, although it is by no means a Spring-specific problem.

Update:

Here's a helper method that returns a list of InputStreams:

public static List<InputStream> loadResources(
        final String name, final ClassLoader classLoader) throws IOException {
    final List<InputStream> list = new ArrayList<InputStream>();
    final Enumeration<URL> systemResources = 
            (classLoader == null ? ClassLoader.getSystemClassLoader() : classLoader)
            .getResources(name);
    while (systemResources.hasMoreElements()) {
        list.add(systemResources.nextElement().openStream());
    }
    return list;
}

Usage:

List<InputStream> resources = loadResources("config.properties", classLoader);
// or:
List<InputStream> resources = loadResources("config.properties", null);

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...