This is a destructuring assignment. The behavior described by @recursive is correct, but it may help to know that it is not limited to the first element. If it had been written with three elements:
function xyz([a, b, c]){...}
Then a, b, and c will all be declared variables available within the function scope, and in this case, would be equal to the first three elements of the array. Further - if the array passed as an argument doesn't have at least three elements, then the remaining elements specified in the parameter (a, b, and c) will exist as being declared, but will have the value of undefined
:
// Example
function destructureThis([a, b, c]){
console.log(a, b, c);
}
var shortArray = [1, 25];
destructureThis(shortArray);
// Prints to console:
// 1 25 undefined
Likewise, if the argument array is larger, additional elements are just ignored, as already noted.
var longerArray = [1, 5, 9, 50, 60];
destructureThis(longerArray);
// Prints to console:
// 1 5 9
Also... this is a recent enough addition to the ECMAScript spec that it should be tested in all your target environments (looking at you IE) if not using Babel or equivalent to transpile it for backwards compatibility.
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