As Google Maps uses Mercator Projection for projecting GPS coordinates, you can't use 'line equation' for gps coordinates, because projection is not linear for gps points.But instead you can use world coordinates
which are linear. Here I have used parametric form of line equation to check whether point
on segment:
function isPointOnSegment( map, gpsPoint1, gpsPoint2, gpsPoint ){
var p1 = map.getProjection().fromLatLngToPoint( gpsPoint1 );
var p2 = map.getProjection().fromLatLngToPoint( gpsPoint2 );
var p = map.getProjection().fromLatLngToPoint( gpsPoint );
var t_x;
var t_y;
//Parametric form of line equation is:
//--------------------------------
// x = x1 + t(x2-x1)
// y = y1 + t(y2-y1)
//--------------------------------
//'p' is on [p1,p2] segment,if 't' is number from [0,1]
//-----Case 1----
// x = x1
// y = y1
//---------------
if( p2.x-p1.x == 0 && p2.y-p1.y == 0){
return p.x == p1.x && p.y == p1.y;
}else
//-----Case 2----
// x = x1
// y = y1 + t(y2-y1)
//---------------
if( p2.x-p1.x == 0 && p2.y-p1.y != 0){
t_y = (p.y - p1.y)/(p2.y-p1.y);
return p.x == p1.x && t_y >= 0 && t_y <= 1;
}else
//-----Case 3----
// x = x1 + t(x2-x1)
// y = y1
//---------------
if( p2.x-p1.x != 0 && p2.y-p1.y == 0){
t_x = (p.x - p1.x)/(p2.x-p1.x);
return p.y == p1.y && t_x >= 0 && t_x <= 1;
}
//-----Case 4----
// x = x1 + t(x2-x1)
// y = y1 + t(y2-y1)
//---------------
t_x = (p.x - p1.x)/(p2.x-p1.x);
t_y = (p.y - p1.y)/(p2.y-p1.y);
return ( t_x == t_y && t_x >= 0 && t_x <= 1 && t_y >= 0 && t_y <= 1);
}
By having clicked point and all segments of polyline, you could use above implemented function and retrieve segment you were looking for.
与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…