First, let me point out that NaN
is a very special value: By definition, it's not equal to itself. That comes from the IEEE-754 standard that JavaScript numbers draw on. The "not a number" value is never equal to itself, even when the bits are an exact match. (Which they aren't necessarily in IEEE-754, it allows for multiple different "not a number" values.) Which is why this even comes up; all other values in JavaScript are equal to themselves, NaN
is just special.
...am I missing some value in JavaScript that will return true for x !== x and false for x != x?
No, you're not. The only difference between !==
and !=
is that the latter will do type coercion if necessary to get the types of the operands to be the same. In x != x
, the types of the operands are the same, and so it's exactly the same as x !== x
.
This is clear from the beginning of the definition of the Abstract Equality Operation:
- ReturnIfAbrupt(x).
- ReturnIfAbrupt(y).
If Type(x) is the same as Type(y), then
Return the result of performing Strict Equality Comparison x === y.
...
The first two steps are basic plumbing. So in effect, the very first step of ==
is to see if the types are the same and, if so, to do ===
instead. !=
and !==
are just negated versions of that.
So if Flanagan is correct that only NaN
will give true for x !== x
, we can be sure that it's also true that only NaN
will give true for x != x
.
Many JavaScript programmers default to using ===
and !==
to avoid some pitfalls around the type coercion the loose operators do, but there's nothing to read into Flanagan's use of the strict vs. loose operator in this case.
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