Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
429 views
in Technique[技术] by (71.8m points)

.net - Why use GetHashCode() over Equals()?

HashSet<T>.Add first compares the results of GetHashCode. If those are equal, it calls Equals.

Now, my understanding is in order to implement GetHashCode, something must be done with the fields of an object. A simple example implementation can be found at What is the best algorithm for an overridden System.Object.GetHashCode?.

In my test comparing both on 1.000.000 pairs of objects filled with random data, performance is more or less equal between the two. GetHashCode is implemented as in the linked example, Equals simply calls Equals on all fields. So why would one want to use GetHashCode over Equals ?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

For some types, an Equals test may be relatively expensive. It typically has to compare every field of the class. In other words, it takes linear time in the size of the class. Bigger classes are more expensive to compare for equality.

Now, what happens if you need to need to compare one object against 1000 others? Calling Equals 1000 times might get expensive. You need to do N*2000 field accesses, if N is the size of the class

GetHashCode instead generates a "mostly unique" integer based on the contents of the class. In other words, the class fields are accessed once. And once you have that, you can compare this integer to the 1000 integers that make up the other objects' hash codes.

Even in such a naive use case, we now only need N*1000 field accesses.

But what if we store the hash code? When we insert an object into a hash set, its hash code is computed once. Now, any time we want to do a lookup in the hash set, we just need to compute one hash code (that of the external object), and then you just have to compare simple integers. So N class field accesses (for the new object whose hash code we need to compute), plus a number of integer comparisons, which vary, depending on the algorithm, but are 1) relatively few, and 2) cheap.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...