Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
134 views
in Technique[技术] by (71.8m points)

javascript singleton question

I just read a few threads on the discussion of singleton design in javascript. I'm 100% new to the Design Pattern stuff but as I see since a Singleton by definition won't have the need to be instantiated, conceptually if it's not to be instantiated, in my opinion it doesn't have to be treated like conventional objects which are created from a blueprint(classes). So my wonder is why not just think of a singleton just as something statically available that is wrapped in some sort of scope and that should be all.

From the threads I saw, most of them make a singleton though traditional javascript

new function(){} 

followed by making a pseudo constructor.

Well I just think an object literal is enough enough:

var singleton = {
   dothis: function(){},
   dothat: function(){}
}

right? Or anybody got better insights?

[update] : Again my point is why don't people just use a simpler way to make singletons in javascript as I showed in the second snippet, if there's an absolute reason please tell me. I'm usually afraid of this kind of situation that I simplify things to much :D

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

I agree with you, the simplest way is to use a object literal, but if you want private members, you could implement taking advantage of closures:

var myInstance = (function() {
  var privateVar;

  function privateMethod () {
    // ...
  }

  return { // public interface
    publicMethod1: function () {
      // private members can be accessed here
    },
    publicMethod2: function () {
      // ...
    }
  };
})();

About the new function(){} construct, it will simply use an anonymous function as a constructor function, the context inside that function will be a new object that will be returned.

Edit: In response to the @J5's comment, that is simple to do, actually I think that this can be a nice example for using a Lazy Function Definition pattern:

function singleton() {
  var instance = (function() {
    var privateVar;

    function privateMethod () {
      // ...
    }

    return { // public interface
      publicMethod1: function () {
          // private members can be accessed here
       },
      publicMethod2: function () {
        // ...
      }
    };
  })();

  singleton = function () { // re-define the function for subsequent calls
    return instance;
  };

  return singleton(); // call the new function
}

When the function is called the first time, I make the object instance, and reassign singleton to a new function which has that object instance in it's closure.

Before the end of the first time call I execute the re-defined singleton function that will return the created instance.

Following calls to the singleton function will simply return the instance that is stored in it's closure, because the new function is the one that will be executed.

You can prove that by comparing the object returned:

singleton() == singleton(); // true

The == operator for objects will return true only if the object reference of both operands is the same, it will return false even if the objects are identical but they are two different instances:

({}) == ({}); // false
new Object() == new Object(); // false

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

1.4m articles

1.4m replys

5 comments

57.0k users

...