Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Post an Article
Welcome To Ask or Share your Answers For Others

Categories

javascript - How do I show a loading spinner when submitting for a partial view in asp.net MVC?

0 votes
381 views
in Technique[技术] by (71.8m points)

javascript - How do I show a loading spinner when submitting for a partial view in asp.net MVC?

I've written an application that loads partial views when you click "Continue". Sometimes the server hangs a little so I'd like to show some sort of loading message or spinner when the user clicks submit so they know the page is doing something.

This is just your standard form but my submit code looks like this(included a field so you can see an example):

                    <div class="form-group">
                    @Html.LabelFor(m => m.JointAdditionalIncomeSource, new { @class = "col-sm-2 control-label" })
                    <div class="col-sm-10">
                        <div class="col-sm-4">
                            @Html.TextBoxFor(m => m.JointAdditionalIncomeSource, new { @class = "form-control", placeholder = "Additional Income Source" })
                            @Html.ValidationMessageFor(m => m.JointAdditionalIncomeSource)
                        </div>
                    </div>
                </div>

            </div>
        </div>
        <div class="form-group">
            <div class="col-md-offset-3 col-sm-10">
                <div class="col-sm-4">
                    <input type="submit" value="Back" id="back" class="btn btn-default" />
                    <input type="submit" value="Continue" id="continue" class="btn btn-default" />
                </div>
            </div>
        </div>

I've looked around on google for ways to do this and so far haven't had any luck. Jquery wouldn't be a bad method to use if anyone has an example of that.

Updates:

This is my current code that is not working.

<head>
<meta charset="utf-8">
<title></title>
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<script src="~/Scripts/jquery-1.10.2.min.js"></script>
<script src="~/Scripts/jquery.unobtrusive-ajax.min.js"></script>


<script>
    $('#continue').submit(function () {
        $('#LoanType').hide();
    });
</script>
<script type="text/javascript">
    function onBegin() {
        $("#divLoading").html('<image src="../Content/ajax-loader.gif" alt="Loading, please wait" />');
    }
    function onComplete() {
        $("#divLoading").html("");
    }
</script>


<body>
    <!--If user has javascript disabled-->
    <noscript>
        <div style="position: fixed; top: 0px; left: 0px; z-index: 3000;
                                  height: 100%; width: 100%; background-color: #FFFFFF">
            <p style="margin-left: 10px">To continue using this application please enable Javascript in your browser.</p>
        </div>
    </noscript>

    <!-- WIZARD -->
    <div id="MyWizard" class="site-padding-top container">


        <div data-target="#step1" id="step1" class="app-bg">

            <div class="form-horizontal">
                <div id="LoanType">
                    <div class="divider-app">
                        <p>Loan Type</p>

                    </div>
                    @using (Ajax.BeginForm("SelectLoanType", new AjaxOptions { HttpMethod = "POST", InsertionMode = InsertionMode.Replace, UpdateTargetId = "step2" }))
                    {
                        <div class="form-group">
                            @Html.LabelFor(m => m.LoanType, new { @class = "col-sm-2 control-label" })
                            <div class="col-sm-10">
                                <div class="col-sm-4">
                                    @Html.DropDownListFor(m => m.LoanType, new SelectList(Model.AllAvailableLoanTypes.Select(x => new { Value = x, Text = x }), "Value", "Text"), new { @class = "form-control", id = "loanType" })
                                </div>
                            </div>
                        </div>

                        <div class="form-group" id="LoanTypeSubmit">
                            <div class="col-lg-offset-3 col-sm-10">
                                <div class="col-sm-4">

                                    <input type="submit" value="Continue" id="continue" class="btn btn-default" />
                                </div>
                            </div>
                        </div>

                    }
                    <div id="divLoading"></div>
                </div>

The delay in the controller is working.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙；凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

Here goes the complete solution -

Lets say you have an ajax controller like this - 

    public ActionResult Ajax()
    {
        return View();
    }

Which serves the following ajax view - 

@{
    ViewBag.Title = "Ajax";
}

<h2>Ajax</h2>

<script src="~/Scripts/jquery-1.10.2.min.js"></script>
<script src="~/Scripts/jquery.unobtrusive-ajax.min.js"></script>
<script type="text/javascript">
    function onBegin() {
        $("#divLoading").html('<image src="../Content/ajax-loader.gif" alt="Loading, please wait" />');
    }
    function onComplete() {
        $("#divLoading").html("");
    }
</script>

@using (Ajax.BeginForm("LoadRules", "Home", new AjaxOptions { UpdateTargetId = "Rules", OnBegin = "onBegin", OnComplete = "onComplete" }))
{
    <input type="submit" value="Load Rules" />
}

<div id="divLoading"></div>

<div id="Rules"></div>

Then when you click on the submit button it will hit the following controller, which has a delay of 5 secs (simulation of long running task) in serving the partial view - 

    public ActionResult LoadRules(DDLModel model)
    {
        System.Threading.Thread.Sleep(5000);
        return PartialView("MyPartial");
    }

and the partial view is a simple view - 

<div>
    This is Partial View
</div>

Here to show the loaded I simply used the following gif file -

enter image description here

when we click on the submit button it will show the progress in the following way -

enter image description here

And once the delay of 5 secs completes on the server side, it will show the partial view -

enter image description here


与恶龙缠斗过久,自身亦成为恶龙；凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界，一个免费开放的程序员编程交流平台！开放，进步，分享！让技术改变生活，让极客改变未来！ Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

Just Browsing Browsing

1.4m articles

1.4m replys

5 comments

57.0k users

Most popular tags

Snow Theme by Q2A Market
Powered by Question2Answer
...