我有一个 NSDictionary 对象数组,每个对象都有一个 EventDate 和 SecurityLevel 。我想先按日期排序,然后按安全级别排序。我该怎么做?
Obj1: SecurityLevel: 5, Date: 20/05/2015 22:03
Obj2: SecurityLevel: 5, Date: 05/03/2015 05:28
Obj3: SecurityLevel: 4, Date: 14/04/2015 11:01
Obj4: SecurityLevel: 4, Date: 07/08/2015 09:31
Obj6: SecurityLevel: 3, Date: 24/04/2015 21:06
Obj5: SecurityLevel: 3, Date: 29/01/2016 22:38
Obj7: SecurityLevel: 2, Date: 02/06/2015 20:49
Obj8: SecurityLevel: 2, Date: 13/07/2015 17:46
Obj9: SecurityLevel: 1, Date: 19/08/2015 07:57
它们应该这样排序:
Obj1: SecurityLevel: 5, Date: 20/05/2015 22:03
Obj2: SecurityLevel: 5, Date: 05/03/2015 05:28
Obj4: SecurityLevel: 4, Date: 07/08/2015 09:31
Obj3: SecurityLevel: 4, Date: 14/04/2015 11:01
Obj5: SecurityLevel: 3, Date: 29/01/2016 22:38
Obj6: SecurityLevel: 3, Date: 24/04/2015 21:06
Obj8: SecurityLevel: 2, Date: 13/07/2015 17:46
Obj7: SecurityLevel: 2, Date: 02/06/2015 20:49
Obj9: SecurityLevel: 1, Date: 19/08/2015 07:57
我做了类似的事情,但它没有按预期工作:
- (NSArray*)sortEventsByDateAndSecurityNSArray*)toSort
{
NSSortDescriptor *securityDescriptor = [[NSSortDescriptor alloc] initWithKey"SeverityLevel" ascending:NO];
NSArray *sortDescriptors = @[securityDescriptor];
NSArray *sortedSecurity = [toSort sortedArrayUsingDescriptors:sortDescriptors];
NSArray *reverseOrderUsingComparator = [sortedSecurity sortedArrayUsingComparator:^(id obj1, id obj2) {
NSDictionary *dictObject1 = (NSDictionary*)obj1;
NSDictionary *dictObject2 = (NSDictionary*)obj2;
NSDate *obj1Date = [Utils stringToDate:[dictObject1 valueForKey"EventDate"] format"dd/MM/yyyy HH:mm"];
NSDate *obj2Date = [Utils stringToDate:[dictObject2 valueForKey"EventDate"] format"dd/MM/yyyy HH:mm"];
return [obj1Date comparebj2Date];
}];
return reverseOrderUsingComparator;
}
Best Answer-推荐答案 strong>
您应该简单地调用 sortedArrayUsingDescriptors: 并使用 2 个描述符数组而不是 1 个:
- (NSArray*)sortEventsByDateAndSecurityNSArray*)toSort
{
NSSortDescriptor *securityDescriptor = [[NSSortDescriptor alloc] initWithKey"SeverityLevel" ascending:NO];
NSSortDescriptor *eventDateDescriptor = [[NSSortDescriptor alloc] initWithKey"EventDate" ascending:NO comparator:^NSComparisonResult(NSString *obj1, NSString *obj2) {
NSDate *obj1Date = [Utils stringToDatebj1 format"dd/MM/yyyy HH:mm"];
NSDate *obj2Date = [Utils stringToDatebj2 format"dd/MM/yyyy HH:mm"];
return [obj1Date comparebj2Date];
}];
NSArray *sortDescriptors = @[securityDescriptor, eventDateDescriptor];
return [toSort sortedArrayUsingDescriptors:sortDescriptors];
}
在这种情况下,第二个排序描述符将仅应用于与第一个排序描述符相等的对象。对于您的情况,这意味着具有相同 SecurityLevel 的对象将按 EventDate 排序。
关于ios - 使用 2 个排序描述符对数组进行排序,我们在Stack Overflow上找到一个类似的问题:
https://stackoverflow.com/questions/35828656/
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