bash - How do i get last sunday date from a given date in unix

Question

get last sunday date as output from a given date (not current date) as input

Example input: 08-30-2017 (%m-%d-%Y)

output should be last sunday: 08-27-2017

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All of the below commands use current day as reference .But i want to give the reference date as input to get last sunday. Please help me with the command.

date +%m-%d-%Y -d "2017-09-10 -7 days"

date +%m-%d-%Y -d "last Sun"

Answer 1

If you deal with a fixed date format %m-%d-%Y, it should be transformed to %Y-%m-%d format to be processed by date function:

d='08-30-2017'
d=${d##*-}-${d%-*}
lst_sunday=$(date -d "$d -$(date -d $d +%u) days" +"%m-%d-%Y")

echo $lst_sunday
08-27-2017

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+%u - interpreted format specificator, day of week (1..7); 1 is Monday