As per the PostgreSQL documentation http://www.postgresql.org/docs/9.0/static/sql-syntax-lexical.html (emphasis mine)
PostgreSQL also accepts "escape" string constants, which are an extension to the SQL standard. An escape string constant is specified by writing the letter E
(upper or lower case) just before the opening single quote, e.g., E'foo'
. (When continuing an escape string constant across lines, write E
only before the first opening quote.) Within an escape string, a backslash character (
) begins a C-like backslash escape sequence, in which the combination of backslash and following character(s) represent a special byte value
The use of \
in your string means that it's escaping an escape sequence, probably to be safe in transit and storage in a .sql
file. The verbatim string actually passed into the ST_GeomFromWKB
function will be:
0101000000321256B312O304Q30034730220275336%E@
These sequences of 3 or 4 characters between slashes would then be interpreted by ST_GeoFromWKB
directly.
The documentation for ST_GeoFromWKB
( http://postgis.org/docs/ST_GeomFromWKB.html ) states:
The ST_GeomFromWKB
function, takes a well-known binary representation of a geometry and a Spatial Reference System ID (SRID
) and creates an instance of the appropriate geometry type. This function plays the role of the Geometry Factory in SQL. This is an alternate name for ST_WKBToSQL
.
Unfortunately it doesn't state what format, exactly, the "well-known binary representation" actually is.
It turns out that the content of the string depends on the coordinate system you're using, which is specified by the SRID
parameter. In this case 4326
corresponds to WGS84
: https://en.wikipedia.org/wiki/World_Geodetic_System#WGS84
You'll need to do further reading and research to untangle that.
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