In 29.5 Atomic types of the C++ Standard November 2014 working draft it states:
- There is a generic class template atomic. The type of the template argument T shall be trivially copyable (3.9). [ Note: Type arguments that are not also statically initializable may be difficult to use. —end note ]
So - as far as I can tell - this:
#include <atomic>
struct Message {
unsigned long int a;
unsigned long int b;
};
std::atomic<Message> sharedState;
int main() {
Message tmp{1,2};
sharedState.store(tmp);
Message tmp2=sharedState.load();
}
should be perfectly valid standard c++14 (and also c++11) code. However, if I don't link libatomic
manually, the command
g++ -std=c++14 <filename>
gives - at least on Fedora 22 (gcc 5.1) - the following linking error:
/tmp/ccdiWWQi.o: In function `std::atomic<Message>::store(Message, std::memory_order)':
main.cpp:(.text._ZNSt6atomicI7MessageE5storeES0_St12memory_order[_ZNSt6atomicI7MessageE5storeES0_St12memory_order]+0x3f): undefined reference to `__atomic_store_16'
/tmp/ccdiWWQi.o: In function `std::atomic<Message>::load(std::memory_order) const':
main.cpp:(.text._ZNKSt6atomicI7MessageE4loadESt12memory_order[_ZNKSt6atomicI7MessageE4loadESt12memory_order]+0x1c): undefined reference to `__atomic_load_16'
collect2: error: ld returned 1 exit status
If I write
g++ -std=c++14 -latomic <filename>
everything is fine.
I know that the standard doesn't say anything about compiler flags or libraries that have to be included, but so far I thought that any standard conformant, single file code can be compiled via the first command.
So why doesn't that apply to my example code? Is there a rational why -latomic
is still necessary, or is it just something that hasn't been addressed by the compiler maintainers, yet?
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