Use length
or sum
:
> length(x[x > 10])
[1] 2
> sum(x > 10)
[1] 2
In the first approach, you would be creating a vector that subsets the values that matches your condition, and then retrieving the length
of the vector.
In the second approach, you are simply creating a logical vector that states whether each value matches the condition (TRUE
) or doesn't (FALSE
). Since TRUE
and FALSE
equate to "1" and "0", you can simply use sum
to get your answer.
Because the first approach requires indexing and subsetting before counting, I am almost certain that the second approach would be faster than the first.
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