Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
436 views
in Technique[技术] by (71.8m points)

monads - Why is there no << in the Haskell standard library?

The Monad class defines a >> method, which sequences two monadic actions:

>> :: Monad m => m a -> m b -> m b

The binding operator >>= has a flipped-argument equivalent, =<<; as do the monadic function composition ('fish') operators >=> and <=<. There doesn't seem to be a <<, though (after a few minutes of Hoogling). Why is this?

Edit: I know it's not a big deal. I just like the way certain lines of code look with the left-pointing operators. x <- doSomething =<< doSomethingElse just looks nicer, with the arrows all going the same way, than x <- doSomethingElse >>= doSomething.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

To the best of my knowledge there is no good reason. Note, that your Monad should also be an instance of Applicative, so you can use <* and *> instead as your sequencing tools.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...