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bash - How to compare hexadecimal numbers with hexadecimal numbers in shell?

How to compare hexadecimal number with hexadecimal numbers in shell?

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At least bash supports hexadecimal integers directly, provided that they are prefixed with 0x:

$ [[ 0xdead -lt 0xcafe ]] && echo yes || echo no
no
$ [[ 0xdead -gt 0xcafe ]] && echo yes || echo no
yes

You just use the comparison operators normally...


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