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in Technique[技术] by (71.8m points)

css - CSS3 White to Transparent Gradient

I'm using CSS3 and RGBA to create a white-to-transparent gradient:

div {
    background-image: -moz-linear-gradient(left, rgba(255, 255, 255, 1), rgba(0, 0, 0, 0));
    background-image: -ms-linear-gradient(left, rgba(255, 255, 255, 1), rgba(0, 0, 0, 0));
    background-image: -webkit-gradient(linear, 0 0, 100% 0, from(rgba(255, 255, 255, 1)), to(rgba(0, 0, 0, 0)));
    background-image: -webkit-linear-gradient(left, rgba(255, 255, 255, 1), rgba(0, 0, 0, 0));
    background-image: -o-linear-gradient(left, rgba(255, 255, 255, 1), rgba(0, 0, 0, 0));
    background-image: linear-gradient(left, rgba(255, 255, 255, 1), rgba(0, 0, 0, 0));
    background-repeat: repeat-x;
    filter: progid:DXImageTransform.Microsoft.gradient(startColorstr='rgba(255, 255, 255, 1)', endColorstr='rgba(0, 0, 0, 0)', GradientType=1);
    padding: 2rem 0;
}

Fiddle here: http://jsfiddle.net/alecrust/fYz45/

However as you'll notice, the gradient is dark in the middle. I'm getting this:

Getting

And I'm expecting this:

Expecting

How can I rectify?

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Change your final step to #FFFFFF00 (rgba(255, 255, 255, 0)) instead of #00000000:

http://jsfiddle.net/fYz45/6/


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