java - How to get the path to the executable when using launch4j?

Question

I'm using launch4j to wrap an executable jar file in my Windows application, but I need to pass references to some of its libraries in through the JVM arguments. The libraries in question reside in the application install directory, and are always located in the same place, relative to the executable.

I'd like to tell launch4j to use executable-relative paths in the JVM options. I know this information is available at the Windows batch script level, but how do you configure launch4j to fetch it?

Edit for clarification: I'm looking specifically for how to make the paths relative to the binary itself, not how to make them relative to the current working directory. The two aren't necessarily the same.

Answer 1

You might add to your launch4j configuration

...
<jre>
...
<opt>-Djna.library.path="%EXEDIR%\path\to\lib"</opt>
<opt>-Djava.library.path="%EXEDIR%\path\to\lib"</opt>
...
</jre>
...

If you need more then a you might seperate several paths by a semikolon as usual.

< opt> Optional, accepts everything you would normally pass to java/javaw launcher: assertion options, system properties and X options. Here you can map environment and special variables EXEDIR (exe's runtime directory), EXEFILE (exe's runtime full file path) to system properties. All variable references must be surrounded with percentage signs and quoted.

Source: http://launch4j.sourceforge.net/docs.html