iterating indexes of items in a list with a condition python

Question

i would want to print out the indexes of the items that are 'H' but it is stuck in one item.

here's my code:

import random

def coinflipping():
    #generating 100 coin flips
    coins = []
    coin_sides = ['H', 'T']
    for i in range(100):
        coins.append(coin_sides[random.randint(0, 1)])
    return coins

sides = coinflipping()
print(sides)

for i in sides:
    if i == 'H':
        print(sides.index(i))

and here's the output:

Answer 1

This is one way of doing it:

import random

def coinflipping():
    #generating 100 coin flips
    coins = []
    coin_sides = ['H', 'T']
    for i in range(100):
        coins.append(coin_sides[random.randint(0, 1)])
    return coins

sides = coinflipping()
print(sides)

for i,t in enumerate(sides):
    if t == 'H':
        print(i)

Remember that index returns the first occurrence of an item. And since sides are your static list it always returns 1 because H is first met in the index 1 in your random case.

You can check enumerate here.

Another way of doing it is this:

a = [np.random.choice(['H','T']) for x in range(100)]
result = [x[0] for x in enumerate(a) if x[1]=='H']

# returns a list of indexes where 'H' was flipped.