Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
880 views
in Technique[技术] by (71.8m points)

sql - How to generate/autoincrement guid on insert without triggers and manual inserts in mysql?

Im revisiting my database and noticed I had some primary keys that were of type INT.

This wasn't unique enough so I thought I would have a guid. I come from a microsoft sql background and in the ssms you can choose type to "uniqeidentifier" and auto increment it.

In mysql however Ive found that you have to make triggers that execute on insert for the tables you want to generate a guide id for. Example:

Table:

CREATE TABLE `tbl_test` (
  `GUID` char(40) NOT NULL,
  `Name` varchar(50) NOT NULL,
  PRIMARY KEY (`GUID`)
) ENGINE=MyISAM DEFAULT CHARSET=latin1;

Trigger:

CREATE TRIGGER `t_GUID` BEFORE INSERT ON `tbl_test`
 FOR EACH ROW begin
 SET new.GUID = uuid();

Alternatively you have to insert the guid yourself in the backend.

Im no DB expert but still remember that triggers cause performance problems.

The above is something I found here and is 9 years old so I was hoping something has changed?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

As far as stated in the documentation, you can use uid() as a column default starting version 8.0.13, so something like this should work:

create table tbl_test (
    guid binary(16) default (uuid_to_bin(uuid())) not null primary key,
    name varchar(50) not null
);

This is pretty much copied from the documentation. I don't have a recent enough version of MySQL at hand to test this.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...