bash - Run expect command inside while loop in shell script

Question

I have list of filenames in a text file,need to transfer each file into server using scp command.I am reading filenames from Read.sh and passing each file name to transfer.sh script but scp is not executing command in this transfer script.If I run transfer.sh alone with passing args its working fine.

List.txt

/home/kittu/file1.txt
/home/kittu/file2.txt
/home/kittu/file3.txt

Read.sh

#!/bin/bash
while read p; do
  echo $p
    ./transfer.sh "$p"
done <List.txt

transfer.sh

#!/usr/bin/expect -f

# get filename from command-line
set f [lindex $argv 0]

spawn scp "$f" [email protected]:/home/user/Desktop/ 
expect "password"
send "123
"
interact

I just run Read.sh as

>./Read.sh

Output:

/home/user/Desktop/file1.txt
spawn scp /home/mbox140/Desktop/test.sh [email protected]:/home/mbox140/Desktop/videos/
[email protected]'s password:

Its not executing next statement.Please suggest me any solution.

Answer 1

Try the below script , The changes are that the Transfer.sh is wrapped into bash.sh. and the reason it waits in the password may be because you are expecting a wrong pattern , try "Password" instead of "password" and after send command, expect for the terminal pattern so that the scp finishes

#!/bin/bash
while read p; do
echo $p
{
    /usr/bin/expect << EOF
    spawn scp $p [email protected]:/home/user/Desktop/
    expect "Password"
    send "123
"
    expect "*#*"
EOF
}
done <List.txt