Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
561 views
in Technique[技术] by (71.8m points)

html - Create a PHP Dropdown menu from a for loop?

I am trying to create a drop down menu with the options of 1,2,3 and 4.

The below code is what I am using just now and the dropdown is empty.

Any idea what I am doing wrong?

<select name="years">
<?php 

for($i=1; $i<=4; $i++)
{

"<option value=".$i.">".$i."</option>";
}
?> 
     <option name="years"> </option>   
        </select> 

            <input type="submit" name="submitYears" value="Year" />
See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

You are not outputting the option tags. Try it like this:

<select name="years">

<?php 

for($i=1; $i<=4; $i++)
{

    echo "<option value=".$i.">".$i."</option>";
}
?> 
     <option name="years"> </option>   
</select> 

<input type="submit" name="submitYears" value="Year" />

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...