Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
463 views
in Technique[技术] by (71.8m points)

c - Calling setns from Go returns EINVAL for mnt namespace

The C code works fine and correctly enters the namespace, but the Go code always seems to return EINVAL from the setns call to enter the mnt namespace. I've tried a number of permutations (including embedded C code with cgo and external .so) on Go 1.2, 1.3 and the current tip.

Stepping through the code in gdb shows that both sequences are calling setns in libc the exact same way (or so it appears to me).

I have boiled what seems to be the issue down to the code below. What am I doing wrong?

Setup

I have a shell alias for starting quick busybox containers:

alias startbb='docker inspect --format "{{ .State.Pid }}" $(docker run -d busybox sleep 1000000)'

After running this, startbb will start a container and output it's PID.

lxc-checkconfig outputs:

Found kernel config file /boot/config-3.8.0-44-generic
--- Namespaces ---
Namespaces: enabled
Utsname namespace: enabled
Ipc namespace: enabled
Pid namespace: enabled
User namespace: missing
Network namespace: enabled
Multiple /dev/pts instances: enabled

--- Control groups ---
Cgroup: enabled
Cgroup clone_children flag: enabled
Cgroup device: enabled
Cgroup sched: enabled
Cgroup cpu account: enabled
Cgroup memory controller: missing
Cgroup cpuset: enabled

--- Misc ---
Veth pair device: enabled
Macvlan: enabled
Vlan: enabled
File capabilities: enabled

uname -a produces:

Linux gecko 3.8.0-44-generic #66~precise1-Ubuntu SMP Tue Jul 15 04:01:04 UTC 2014 x86_64 x86_64 x86_64 GNU/Linux

Working C code

The following C code works fine:

#include <errno.h>
#include <sched.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <fcntl.h>

main(int argc, char* argv[]) {
    int i;
    char nspath[1024];
    char *namespaces[] = { "ipc", "uts", "net", "pid", "mnt" };

    if (geteuid()) { fprintf(stderr, "%s
", "abort: you want to run this as root"); exit(1); }

    if (argc != 2) { fprintf(stderr, "%s
", "abort: you must provide a PID as the sole argument"); exit(2); }

    for (i=0; i<5; i++) {
        sprintf(nspath, "/proc/%s/ns/%s", argv[1], namespaces[i]);
        int fd = open(nspath, O_RDONLY);

        if (setns(fd, 0) == -1) { 
            fprintf(stderr, "setns on %s namespace failed: %s
", namespaces[i], strerror(errno));
        } else {
            fprintf(stdout, "setns on %s namespace succeeded
", namespaces[i]);
        }

        close(fd);
    }
}

After compiling with gcc -o checkns checkns.c, the output of sudo ./checkns <PID> is:

setns on ipc namespace succeeded
setns on uts namespace succeeded
setns on net namespace succeeded
setns on pid namespace succeeded
setns on mnt namespace succeeded

Failing Go code

Conversely, the following Go code (which should be identical) doesn't work quite as well:

package main

import (
    "fmt"
    "os"
    "path/filepath"
    "syscall"
)

func main() {
    if syscall.Geteuid() != 0 {
        fmt.Println("abort: you want to run this as root")
        os.Exit(1)
    }

    if len(os.Args) != 2 {
        fmt.Println("abort: you must provide a PID as the sole argument")
        os.Exit(2)
    }

    namespaces := []string{"ipc", "uts", "net", "pid", "mnt"}

    for i := range namespaces {
        fd, _ := syscall.Open(filepath.Join("/proc", os.Args[1], "ns", namespaces[i]), syscall.O_RDONLY, 0644)
        err, _, msg := syscall.RawSyscall(308, uintptr(fd), 0, 0) // 308 == setns

        if err != 0 {
            fmt.Println("setns on", namespaces[i], "namespace failed:", msg)
        } else {
            fmt.Println("setns on", namespaces[i], "namespace succeeded")
        }

    }
}

Instead, running sudo go run main.go <PID> produces:

setns on ipc namespace succeeded
setns on uts namespace succeeded
setns on net namespace succeeded
setns on pid namespace succeeded
setns on mnt namespace failed: invalid argument
See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)
Waitting for answers

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...