This can be done with regular expressions:
import re
s = 'Name of value 1.111E-11 Next Name 444.4'
match_number = re.compile('-? *[0-9]+.?[0-9]*(?:[Ee] *-? *[0-9]+)?')
final_list = [float(x) for x in re.findall(match_number, s)]
print final_list
output:
[1.111e-11, 444.4]
Note that the pattern I wrote above depends on at least one digit existing to the left of the decimal point.
EDIT:
Here's a tutorial and reference I found helpful for learning how to write regex patterns.
Since you asked for an explanation of the regex pattern:
'-? *[0-9]+.?[0-9]*(?:[Ee] *-? *[0-9]+)?'
One piece at a time:
-? optionally matches a negative sign (zero or one negative signs)
* matches any number of spaces (to allow for formatting variations like - 2.3 or -2.3)
[0-9]+ matches one or more digits
.? optionally matches a period (zero or one periods)
[0-9]* matches any number of digits, including zero
(?: ... ) groups an expression, but without forming a "capturing group" (look it up)
[Ee] matches either "e" or "E"
* matches any number of spaces (to allow for formats like 2.3E5 or 2.3E 5)
-? optionally matches a negative sign
* matches any number of spaces
[0-9]+ matches one or more digits
? makes the entire non-capturing group optional (to allow for the presence or absence of the exponent - 3000 or 3E3
note: d is a shortcut for [0-9], but I'm jut used to using [0-9].
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