scala - Convert a List into an Option if it is populated

Question

I have a method that should convert a list to an Option of an object, or None if the list is empty.

def listToOption(myList: List[Foo]): Option[Bar] = {
  if(myList.nonEmpty) Some(Bar(myList))
  else None
}

case class Bar(fooList: List[Foo]) {}

For some reason, my solution feels rather inelegant, and not the Scala way. It seems I should be able to use a method on List to do this sort of thing, but I can't wrap my head around it.

Is there a more Scala-like way to do this?

Answer 1

Lee's answer is good, but I think this corresponds to the intention a bit more clearly:

Option(myList).filter(_.nonEmpty).map(Bar)