html - How to create a custom shape - css

Question

I would like to create a custom shape like this image :

how can I do ?

My CSS :

#chevron { 
  position: relative;
  text-align: center;
  padding: 12px;
  margin-bottom: 6px;
  height: 60px; 
  width: 200px; }

#chevron:before { 
  content: ''; 
  position: absolute;
  top: 0; 
  left: 0;
  height: 100%;
  width: 51%;
  background: #337AB7;
  -webkit-transform: skew(0deg, 6deg);    -moz-transform: skew(0deg, 6deg);
  -ms-transform: skew(0deg, 6deg);
  -o-transform: skew(0deg, 6deg);
  transform: skew(0deg, 6deg); }

#chevron:after { 
  content: ''; 
  position: absolute;
  top: 0; 
  right: 0;
  height: 100%;
  width: 50%;
  background: #337AB7;
  -webkit-transform: skew(0deg, -6deg); -moz-transform: skew(0deg, -6deg); -ms-transform: skew(0deg, -6deg); -o-transform: skew(0deg, -6deg); transform: skew(0deg, -6deg); }

My HTML file :

<div id="chevron">

</div>

But my result isn't what I want :

Answer 1

• Add the background color to the parent div to fill in the gap
• Place the border-radius on the parent div to create the two rounded corners
• Move the :before and :after down slightly with top: 20px so they don't peak out the top of the div

Example

Here is a fiddle of the below:

#chevron {
  width: 350px;
  height: 100px;
  background: #337AB7;
  border-radius: 10px 10px 0 0;
  position: relative;
}
#chevron:before {
  content: '';
  position: absolute;
  top: 20px;
  left: 0;
  height: 100%;
  width: 51%;
  background: #337AB7;
  -webkit-transform: skew(0deg, 6deg);
  -moz-transform: skew(0deg, 6deg);
  -ms-transform: skew(0deg, 6deg);
  -o-transform: skew(0deg, 6deg);
  transform: skew(0deg, 6deg);
}
#chevron:after {
  content: '';
  position: absolute;
  top: 20px;
  right: 0;
  height: 100%;
  width: 50%;
  background: #337AB7;
  -webkit-transform: skew(0deg, -6deg);
  -moz-transform: skew(0deg, -6deg);
  -ms-transform: skew(0deg, -6deg);
  -o-transform: skew(0deg, -6deg);
  transform: skew(0deg, -6deg);
}

<div id="chevron"></div>