bash - How to define a function on one line

Question

Often when moving files around, I need to do the opposite later. So in my .bashrc I included this working code:

rmv() {
  mv $2/${1##*/} ${1%/*}
}

Now I wonder why I can't write this as a single liner. This is what I tried:

rmv() {mv $2/${1##*/} ${1%/*}}

If I do so, I get this error:

-bash: .bashrc: line 1: syntax error near unexpected token `{mv'

Answer 1

In Bash, { is not automatically recognized as a special/separate token from what's around it. So you need whitespace between { and mv.

Additionally:

• } needs to be the start of a command; so if it's not on its own line, you need ; to terminate the previous command.
• It's a best practice to always use double-quotes around any parameter expansion, since otherwise you'll get bizarre behaviors when the parameters include whitespace or special characters.

So:

rmv() { mv "$2/${1##*/}" "${1%/*}" ; }