Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
850 views
in Technique[技术] by (71.8m points)

javascript - Promise.all with nested Promise.all

I've nested arrays, I'm able to retrieve promises for the 2nd level array but not sure how to implement a then once top level finishes as well.

result.forEach(function(entity){ // outer list ???
    return Promise.all(entity.urls.map(function(item){
        return requestURL(item.href);
    }));
});

for instance if results has two or more items and each item has 10 or more urls to fetch, how would we implement then of [Promise.all][1] for all the promises. Native solution please.

Basically to handle nested arrays of promises in a right way.

Data Structure:

var result = [
    {
        urls: [
            {href: "link1"},
            {href: "link2"},
            {href: "link3"}
        ]
    },
    {
        urls: [
            {href: "link4"},
            {href: "link5"},
            {href: "link6"}
        ]
    }
];
See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

Use map instead of forEach, and wrap it inside another Promise.all call.

var arr = [
  {subarr: [1,2,3]},
  {subarr: [4,5,6]},
  {subarr: [7,8,9]}
];
function processAsync(n) {
  return new Promise(function(resolve) {
    setTimeout(
      function() { resolve(n * n); },
      Math.random() * 1e3
    );
  });
}
Promise.all(arr.map(function(entity){
  return Promise.all(entity.subarr.map(function(item){
    return processAsync(item);
  }));
})).then(function(data) {
  console.log(data);
});

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...