swift - How to render a whole UITableView as an UIImage in iOS?

Question

I have simple UITableView with some data. The table's height is greater than the screen size. Now I need to catch screenshot of this table (a whole table). I know that cells after the content are dequeued, but maybe there is a way how to capture this. isn't it?

Answer 1

Try this:

 func generateImage(tblview:UITableView) ->UIImage{
        UIGraphicsBeginImageContext(tblview.contentSize);
        tblview.scrollToRowAtIndexPath(NSIndexPath(forRow: 0, inSection: 0), atScrollPosition: UITableViewScrollPosition.Top, animated: false)
        tblview.layer.renderInContext(UIGraphicsGetCurrentContext())
        let row = tblview.numberOfRowsInSection(0)
        let numberofRowsThatShowOnScreen = 4
        var scrollCount = row / numberofRowthatShowinscreen
        
        for var i = 0; i < scrollCount; i++ {
            tblview.scrollToRowAtIndexPath(NSIndexPath(forRow: (i+1) * numberofRowsThatShowOnScreen, inSection: 0), atScrollPosition: UITableViewScrollPosition.Top, animated: false)
            tblview.layer.renderInContext(UIGraphicsGetCurrentContext())
        }
        
        let image:UIImage = UIGraphicsGetImageFromCurrentImageContext()
        UIGraphicsEndImageContext();
        return image;
}


        
 

and after call method like this.

 var imageView = UIImageView()
     imageView.image = generateImage(tableView)