Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
354 views
in Technique[技术] by (71.8m points)

c++ - Error subtracting floating point numbers when passing through 0.0

The following program:

#include <stdio.h>

int main()
{
    double val = 1.0;
    int i;

    for (i = 0; i < 10; i++)
    {
        val -= 0.2;
        printf("%g %s
", val, (val == 0.0 ? "zero" : "non-zero"));
    }

    return 0;
}

Produces this output:

0.8 non-zero
0.6 non-zero
0.4 non-zero
0.2 non-zero
5.55112e-17 non-zero
-0.2 non-zero
-0.4 non-zero
-0.6 non-zero
-0.8 non-zero
-1 non-zero

Can anyone tell me what is causing the error when subtracting 0.2 from 0.2? Is this a rounding error or something else? Most importantly, how do I avoid this error?

EDIT: It looks like the conclusion is to not worry about it, given 5.55112e-17 is extremely close to zero (thanks to @therefromhere for that information).

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

Its because floating points numbers can not be stored in memory in exact value. So it is never safe to use == in floating point values. Using double will increase the precision, but again that will not be exact. The correct way to compare a floating point value is to do something like this:

val == target;   // not safe

// instead do this
// where EPS is some suitable low value like 1e-7
fabs(val - target) &lt EPS; 

EDIT: As pointed in the comments, the main reason of the problem is that 0.2 can't be stored exactly. So when you are subtracting it from some value, every time causing some error. If you do this kind of floating point calculation repeatedly then at certain point the error will be noticeable. What I am trying to say is that all floating points values can't be stored, as there are infinites of them. A slight wrong value is not generally noticeable but using that is successive computation will lead to higher cumulative error.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...