Flexible filter solution with multi-criteria
This approach allows a multi criteria search defining a search array and using the Application.Index
function in an advanced way. This solution allows to avoid loops or ReDim s
nearly completely in only a few steps:
- [0] Define a criteria array, e.g.
criteria = Array("condenser", "pump")
.
- [1] Assign data A:Z to a 2-dim datafield array:
v = ws.Range("A2:Z" & n)
, where n is the last row number and ws
the set source sheet object.
Caveat: If your basic data contain any date formats, it's strictly recommended to use the .Value2
property instead of the automatic default assignment via .Value
- for further details see comment.
- [2] Search through column
G
(=7th col) and build an array containing the found rows via a helper function: a = buildAr(v, 7, criteria)
.
- [3] Filter based on this array
a
using the Application.Index
function and reduce the returned column values to only A,B,X,Z
.
- [4] Write the resulting datafield array
v
to your target sheet using one command only: e.g. ws2.Range("A2").Resize(UBound(v), UBound(v, 2)) = v
, where ws2 is the set target sheet object.
Main procedure MultiCriteria
Option Explicit ' declaration head of code module
Dim howMany& ' findings used in both procedures
Sub MultiCriteria()
' Purpose: copy defined columns of filtered rows
Dim i&, j&, n& ' row or column counters
Dim a, v, criteria, temp ' all together variant
Dim ws As Worksheet, ws2 As Worksheet ' declare and set fully qualified references
Set ws = ThisWorkbook.Worksheets("Sheet1") ' <<~~ change to your SOURCE sheet name
Set ws2 = ThisWorkbook.Worksheets("Sheet2") ' <<~~ assign to your TARGET sheet name
' [0] define criteria
criteria = Array("condenser", "pump") ' <<~~ user defined criteria
' [1] Get data from A1:Z{n}
n = ws.Range("A" & Rows.Count).End(xlUp).Row ' find last row number n
v = ws.Range("A2:Z" & n) ' get data cols A:Z and omit header row
' [2] build array containing found rows
a = buildAr(v, 7, criteria) ' search in column G = 7
' [3a] Row Filter based on criteria
v = Application.Transpose(Application.Index(v, _
a, _
Application.Evaluate("row(1:" & 26 & ")"))) ' all columns
' [3b] Column Filter A,B,X,Z
v = Application.Transpose(Application.Transpose(Application.Index(v, _
Application.Evaluate("row(1:" & UBound(a) - LBound(a) + 1 & ")"), _
Array(1, 2, 24, 26)))) ' only cols A,B,X,Z
' [3c] correct rows IF only one result row found or no one
If howMany <= 1 Then v = correct(v)
' [4] Copy results array to target sheet, e.g. starting at A2
ws2.Range("A2").offset(0, 0).Resize(UBound(v), UBound(v, 2)) = v
End Sub
Possible addition to check the filtered results array
If you want to control the results array in the VB Editor's immediate window, you could add the following section '[5]
to the above code:
' [5] [Show results in VB Editor's immediate window]
Debug.Print "2-dim Array Boundaries (r,c): " & _
LBound(v, 1) & " To " & UBound(v, 1) & ", " & _
LBound(v, 2) & " To " & UBound(v, 2)
For i = 1 To UBound(v)
Debug.Print i, Join(Application.Index(v, i, 0), " | ")
Next i
1st helper function buildAr()
Function buildAr(v, ByVal vColumn&, criteria) As Variant
' Purpose: Helper function to check criteria array (e.g. "condenser","pump")
' Note: called by main function MultiCriteria in section [2]
Dim found&, found2&, i&, n&, ar: ReDim ar(0 To UBound(v) - 1)
howMany = 0 ' reset boolean value to default
For i = LBound(v) To UBound(v)
found = 0
On Error Resume Next ' avoid not found error
found = Application.Match(v(i, vColumn), criteria, 0)
If found > 0 Then
ar(n) = i
n = n + 1
End If
Next i
If n < 2 Then
howMany = n: n = 2
Else
howMany = n
End If
ReDim Preserve ar(0 To n - 1)
buildAr = ar
End Function
2nd helper function correct()
Function correct(v) As Variant
' Purpose: reduce array to one row without changing Dimension
' Note: called by main function MultiCriteria in section [3c]
Dim j&, temp: If howMany > 1 Then Exit Function
ReDim temp(1 To 1, LBound(v, 2) To UBound(v, 2))
If howMany = 1 Then
For j = 1 To UBound(v, 2): temp(1, j) = v(1, j): Next j
ElseIf howMany = 0 Then
temp(1, 1) = "N/A# - No results found!"
End If
correct = temp
End Function
Edit I. due to your comment
"In column G I have a sentence for example (repair to do on the condenser) and I would like that as soon as the word "condenser" appears it implies it respects my criteria I tried ("* condenser*", "cex") like if filename like "book" but it doesn't work on an array, is there a method for that?"
Simply change the logic in helper function buildAr()
to search via wild cards by means of a second loop over the search terms (citeria
):
Function buildAr(v, ByVal vColumn&, criteria) As Variant
' Purpose: Helper function to check criteria array (e.g. "condenser","pump")
' Note: called by main function MultiCriteria in section [2]
Dim found&, found2&, i&, j&, n&, ar: ReDim ar(0 To UBound(v) - 1)
howMany = 0 ' reset boolean value to default
For i = LBound(v) To UBound(v)
found = 0
On Error Resume Next ' avoid not found error
' ' ** original command commented out**
' found = Application.Match(v(i, vColumn), criteria, 0)
For j = LBound(criteria) To UBound(criteria)
found = Application.Match("*" & criteria(j) & "*", Split(v(i, vColumn) & " ", " "), 0)
If found > 0 Then ar(n) = i: n = n + 1: Exit For
Next j
Next i
If n < 2 Then
howMany = n: n = 2
Else
howMany = n
End If
ReDim Preserve ar(0 To n - 1)
buildAr = ar
End Function
Edit II. due to last comment - check for existing values in column X only
"... I saw the change you did but I wanted to apply the last simpler idea, (last comment ) not using the wild Card but instead to check if there's a value in column X."
Simply hange the logic in the helper function to check for existing values only by measuring the length of trimmed values in column 24 (=X) and change the calling code in the main procedure to
' [2] build array containing found rows
a = buildAr2(v, 24) ' << check for value in column X = 24
Note: Section [0] defining criteria won't be needed in this case.
Version 2 of helper function
Function buildAr2(v, ByVal vColumn&, Optional criteria) As Variant
' Purpose: Helper function to check for existing value e.g. in column 24 (=X)
' Note: called by main function MultiCriteria in section [2]
Dim found&, found2&, i&, n&, ar: ReDim ar(0 To UBound(v) - 1)
howMany = 0 ' reset boolean value to default
For i = LBound(v) To UBound(v)
If Len(Trim(v(i, vColumn))) > 0 Then
ar(n) = i
n = n + 1
End If
Next i
If n < 2 Then
howMany = n: n = 2
Else
howMany = n
End If
ReDim Preserve ar(0 To n - 1)
buildAr2 = ar
End Function