Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
512 views
in Technique[技术] by (71.8m points)

python - How can I split a string and form a multi-level nested dictionary?

I have a string like

foo/bar/baz

I also have val=1 for example. Is there a clean way to split the foo/bar/baz into a multi-dimensional dict with the last item in the dict to equal 1. So it would look like

{'foo': {'bar': {'baz': 1}}}
See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

You can use reduce and reversed functions, like this

>>> reduce(lambda res, cur: {cur: res}, reversed("foo/bar/baz".split("/")), 1)
{'foo': {'bar': {'baz': 1}}}

If you are using Python 3.x, then you need to import reduce from functools

>>> from functools import reduce
>>> reduce(lambda res, cur: {cur: res}, reversed("foo/bar/baz".split("/")), 1)
{'foo': {'bar': {'baz': 1}}}

Here, the last argument to reduce is the starting value. It will take values one by one from the iterable passed, call the function with the result and the current value and then the next time onwards, the last result will be the first argument and the current value as the second argument. When the iterable is exhausted, it will return the result.

So, the execution would have gone, step-by-step, as following

Let's say func is the lambda function and it gets repeatedly called like this

func(1, "baz")                   => {"baz": 1}
func({"baz": 1}, "bar")          => {"bar": {"baz": 1}}
func({"bar": {"baz": 1}}, "foo") => {"foo": {"bar": {"baz": 1}}}

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...