Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
443 views
in Technique[技术] by (71.8m points)

c# - Displaying progress dialog only if a task did not finish in specified time

I have a little service that uploads an image, and I use it like this:

ImageInfo result = await service.UploadAsync(imagePath);

What I'd like to do is to display a progress dialog, but only if the upload operation takes more than, say, 2 seconds. After the upload is done, I want to close the progress dialog.

I made a crude solution using Task/ContinueWith, but I was hoping for a more "elegant" way.

How can I achieve this using async/await?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

May be something like this?

var uploadTask = service.UploadAsync(imagePath);
var delayTask = Task.Delay(1000);//Your delay here
if (await Task.WhenAny(new[] { uploadTask, delayTask }) == delayTask)
{
    //Timed out ShowProgress
    ShowMyProgress();
    await uploadTask;//Wait until upload completes
    //Hide progress
    HideProgress();
}

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...