python - REGEX-String and escaped quote

Question

How to get what is between the quotes in the following two texts ?

text_1 = r""" "Some text on "two" lines with a backslash escaped" 
     + "Another text on "three" lines" """

text_2 = r""" "Some text on "two" lines with a backslash escaped" + "Another text on "three" lines" """

The problem for me is that the quotes should be ignored if they are escaped, but there is the possibilty to have the backslash escaped.

I would like to obtain the following groups.

[
    r'Some text on "two" lines with a backslash escaped\',
    r'Another text on "three" lines'
]

Answer 1

"(?:\.|[^"\])*"

matches a quoted string, including any escaped characters that occur within it.

Explanation:

"       # Match a quote.
(?:     # Either match...
 \.    # an escaped character
|       # or
 [^"\] # any character except quote or backslash.
)*      # Repeat any number of times.
"       # Match another quote.