You can use re.findall()
and the ((.)2*)
regular expression:
>>> [item[0] for item in re.findall(r"((.)2*)", string)]
['555', '44', '3', '55']
the key part is inside the outer capturing group - (.)2*
. Here we capture a single character via (.)
then reference this character by the group number: 2
. The group number is 2 because we have an outer capturing group with number 1. *
means 0 or more times.
You could've also solved it with a single capturing group and re.finditer()
:
>>> [item.group(0) for item in re.finditer(r"(.)1*", string)]
['555', '44', '3', '55']
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