Application.FollowHyperLink() has problems with security, especially when opening files on a network drive. See e.g. here: http://blogannath.blogspot.de/2011/04/microsoft-access-tips-tricks-opening.html
A better method is the ShellExecute() API function.
Essentially it looks like this (trimmed from http://access.mvps.org/access/api/api0018.htm ):
' This code was originally written by Dev Ashish.
' http://access.mvps.org/access/api/api0018.htm
Private Declare Function apiShellExecute Lib "shell32.dll" _
Alias "ShellExecuteA" _
(ByVal hwnd As Long, _
ByVal lpOperation As String, _
ByVal lpFile As String, _
ByVal lpParameters As String, _
ByVal lpDirectory As String, _
ByVal nShowCmd As Long) _
As Long
Public Const WIN_NORMAL = 1 'Open Normal
Private Const ERROR_SUCCESS = 32&
Public Function fHandleFile(stFile As String) As Boolean
Dim lRet As Long
lRet = apiShellExecute(hWndAccessApp(), "Open", stFile, vbNullString, vbNullString, WIN_NORMAL)
If lRet > ERROR_SUCCESS Then
' OK
fHandleFile = True
Else
Select Case lRet
' Handle various errors
End Select
fHandleFile = False
End If
End Function
Now for your listbox:
Set it to 2 columns, the first being the model name, the second the file path.
Set the column width of the second column to 0, so it will be invisible.
And in the doubleclick event, call fHandleFile with the second column (file path):
Private Sub lstManuals_DblClick(Cancel As Integer)
Call fHandleFile(Me.lstManuals.Column(1))
End Sub
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