It's about 135 points to a meter.
A physicsBody left to fall from stationary under gravity of 9.8m/s travelled 660 points in 1.00806862953687s (1.01s), with a velocity of 1342.8162841796875m/s (1342.82).
Doing the maths to 2 decimal places, we can use both the equations of distance travelled and speed to calculate the number of points per meter through 2 different calculations:
Using v=u+at (u=0, a=9.8, t=1.01s), we can calculate that after 1.01s, v is 1.01 * 9.8 = 9.90m/s. The physicsbody's velocity is 1342.85, Therefore 9.90m/s = 1342.82 points/s so 1m = 135.6 points.
Or, using s=ut+?at2, to calculate the distance travelled after time t, we get s = 0.5x9.8x1.01 = 4.95m. Therefore 4.95m = 660point; 1m = 133.3 points.
If you do the maths with the full precision, you get a figure of 137 points.
Using the timings after approx 2 seconds gives a figure of 133.4 points/m from the acceleration formula and 133.7points/m from the distance formula
What is odd is that the SKPhysicsBody class reference described the velocity property as being in meters/second, but it definitely appears to be in points per second.
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